The drawing shows a circus clown who weighs 792 N. The coefficient of static friction...?
A circus clown weighs 792 N. The coefficient of static friction between the clown's feet and the ground is 0.537. He pulls vertically downward on a rope that passes around three pulleys and is tied around his feet. What is the minimum pulling force that the clown must exert to yank his feet out from under himself?
just looking for some help!
first answer is incorrect, but the pullys are situated where one is at the ground and then one is directly vertical to that at the top and then finally one is directly horizontal to that one where the clown is holding on to that one....
How are the 3 pulleys situated? It appears from the question that the pulleys are situated so that the rope pulls horizontally on the feet. Is that correct? Are the pulleys connected so that there is a mechanical advantage?
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